What are the solutions to the equation 8f^2+8f+2=0 ?

The solutions to the equation 8f^2+8f+2=0 are f=-1/2

Find the zeros of 8f^2+8f+2=0

The zeros of 8f^2+8f+2=0 are f=-1/2

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8 f^{2} + 8 f + 2 = 0

f = - \frac{1}{2}

Decimal Notation

f = - 0.5

Solution steps

8 f^{2} + 8 f + 2 = 0

Solve with the quadratic formula

f_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 8 \cdot 2}{2 \cdot 8}

8^{2} - 4 \cdot 8 \cdot 2 = 0

f_{1, 2} = \frac{- 8 \pm 0}{2 \cdot 8}

f = \frac{- 8}{2 \cdot 8}

\frac{- 8}{2 \cdot 8} = - \frac{1}{2}

f = - \frac{1}{2}

The solution to the quadratic equation is:

f = - \frac{1}{2}

4 x^{2} - 30 x + 72 = 0

- x^{2} + 16 x = 0

x, x^{2} + 14 x + 34 = 1

v^{2} + 20 v + 84 = 0

8 x^{2} + 2 x = 1

What are the solutions to the equation 8f^2+8f+2=0 ?
The solutions to the equation 8f^2+8f+2=0 are f=-1/2
Find the zeros of 8f^2+8f+2=0
The zeros of 8f^2+8f+2=0 are f=-1/2