What are the solutions to the equation solvefor x,x^2+14x+34=1 ?

The solutions to the equation solvefor x,x^2+14x+34=1 are x=-3,x=-11

Find the zeros of solvefor x,x^2+14x+34=1

The zeros of solvefor x,x^2+14x+34=1 are x=-3,x=-11

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x, x^{2} + 14 x + 34 = 1

x = - 3, x = - 11

Solution steps

x^{2} + 14 x + 34 = 1

Move

1

to the left side

x^{2} + 14 x + 33 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 14 \pm 1 4 ^{2} - 4 \cdot 1 \cdot 33}{2 \cdot 1}

1 4^{2} - 4 \cdot 1 \cdot 33 = 8

x_{1, 2} = \frac{- 14 \pm 8}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 14 + 8}{2 \cdot 1}, x_{2} = \frac{- 14 - 8}{2 \cdot 1}

x = \frac{- 14 + 8}{2 \cdot 1} : - 3

x = \frac{- 14 - 8}{2 \cdot 1} : - 11

The solutions to the quadratic equation are:

x = - 3, x = - 11

v^{2} + 20 v + 84 = 0

8 x^{2} + 2 x = 1

x^{2} - 7 x + 12 = 0, a = 1 b = - 7 c = 12

x^{2} + 64 x + 16 = 0

9 x (4 - x) = 31

What are the solutions to the equation solvefor x,x^2+14x+34=1 ?
The solutions to the equation solvefor x,x^2+14x+34=1 are x=-3,x=-11
Find the zeros of solvefor x,x^2+14x+34=1
The zeros of solvefor x,x^2+14x+34=1 are x=-3,x=-11