What are the solutions to the equation 8x^2+2x=1 ?

The solutions to the equation 8x^2+2x=1 are x= 1/4 ,x=-1/2

Find the zeros of 8x^2+2x=1

The zeros of 8x^2+2x=1 are x= 1/4 ,x=-1/2

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8 x^{2} + 2 x = 1

x = \frac{1}{4}, x = - \frac{1}{2}

Decimal Notation

x = 0.25, x = - 0.5

Solution steps

8 x^{2} + 2 x = 1

Move

1

to the left side

8 x^{2} + 2 x - 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 8 ( - 1 )}{2 \cdot 8}

2^{2} - 4 \cdot 8 (- 1) = 6

x_{1, 2} = \frac{- 2 \pm 6}{2 \cdot 8}

Separate the solutions

x_{1} = \frac{- 2 + 6}{2 \cdot 8}, x_{2} = \frac{- 2 - 6}{2 \cdot 8}

x = \frac{- 2 + 6}{2 \cdot 8} : \frac{1}{4}

x = \frac{- 2 - 6}{2 \cdot 8} : - \frac{1}{2}

The solutions to the quadratic equation are:

x = \frac{1}{4}, x = - \frac{1}{2}

x^{2} - 7 x + 12 = 0, a = 1 b = - 7 c = 12

x^{2} + 64 x + 16 = 0

9 x (4 - x) = 31

x^{2} = 1^{2} + (\frac{1}{2})^{2}

60 = 50 + 2 t - 0.0625 t^{2}

What are the solutions to the equation 8x^2+2x=1 ?
The solutions to the equation 8x^2+2x=1 are x= 1/4 ,x=-1/2
Find the zeros of 8x^2+2x=1
The zeros of 8x^2+2x=1 are x= 1/4 ,x=-1/2