What are the solutions to the equation x^2=1^2+(1/2)^2 ?

The solutions to the equation x^2=1^2+(1/2)^2 are x=(sqrt(5))/2 ,x=-(sqrt(5))/2

Find the zeros of x^2=1^2+(1/2)^2

The zeros of x^2=1^2+(1/2)^2 are x=(sqrt(5))/2 ,x=-(sqrt(5))/2

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x^{2} = 1^{2} + (\frac{1}{2})^{2}

x = \frac{5}{2}, x = - \frac{5}{2}

Decimal Notation

x = 1.11803 \dots, x = - 1.11803 \dots

Solution steps

x^{2} = 1^{2} + (\frac{1}{2})^{2}

Simplify

1^{2} + (\frac{1}{2})^{2} : \frac{5}{4}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{5}{4}, x = - \frac{5}{4}

\frac{5}{4} = \frac{5}{2}

- \frac{5}{4} = - \frac{5}{2}

x = \frac{5}{2}, x = - \frac{5}{2}

60 = 50 + 2 t - 0.0625 t^{2}

- 4 x^{2} + 2 x - 5 = 0

6 x^{2} + 6 x = 1

(x - 5)^{2} - 2 = 79

x, 0 = 1.35 x^{2} - 11.74 x + 8.62

What are the solutions to the equation x^2=1^2+(1/2)^2 ?
The solutions to the equation x^2=1^2+(1/2)^2 are x=(sqrt(5))/2 ,x=-(sqrt(5))/2
Find the zeros of x^2=1^2+(1/2)^2
The zeros of x^2=1^2+(1/2)^2 are x=(sqrt(5))/2 ,x=-(sqrt(5))/2