What are the solutions to the equation 1.5x^2-45x-45=0 ?

The solutions to the equation 1.5x^2-45x-45=0 are x=15+sqrt(255),x=15-sqrt(255)

Find the zeros of 1.5x^2-45x-45=0

The zeros of 1.5x^2-45x-45=0 are x=15+sqrt(255),x=15-sqrt(255)

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1.5 x^{2} - 45 x - 45 = 0

x = 15 + 255, x = 15 - 255

Decimal Notation

x = 30.96871 \dots, x = - 0.96871 \dots

Solution steps

1.5 x^{2} - 45 x - 45 = 0

Multiply both sides by

10

15 x^{2} - 450 x - 450 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 450 ) \pm ( - 450 ) ^{2} - 4 \cdot 15 ( - 450 )}{2 \cdot 15}

(- 450)^{2} - 4 \cdot 15 (- 450) = 30255

x_{1, 2} = \frac{- ( - 450 ) \pm 30 255}{2 \cdot 15}

Separate the solutions

x_{1} = \frac{- ( - 450 ) + 30 255}{2 \cdot 15}, x_{2} = \frac{- ( - 450 ) - 30 255}{2 \cdot 15}

x = \frac{- ( - 450 ) + 30 255}{2 \cdot 15} : 15 + 255

x = \frac{- ( - 450 ) - 30 255}{2 \cdot 15} : 15 - 255

The solutions to the quadratic equation are:

x = 15 + 255, x = 15 - 255

x, (x - 1)^{2} + y^{2} = z

x, s (x) = (- 2 x^{2} - 7 x + 4) - (x^{2} - 2 x - 1)

x^{2} + 2 x + n^{2} = 0

- 16 t^{2} + 32 t + 384 = 0

y (y + 5) = 750

What are the solutions to the equation 1.5x^2-45x-45=0 ?
The solutions to the equation 1.5x^2-45x-45=0 are x=15+sqrt(255),x=15-sqrt(255)
Find the zeros of 1.5x^2-45x-45=0
The zeros of 1.5x^2-45x-45=0 are x=15+sqrt(255),x=15-sqrt(255)