What are the solutions to the equation 3t^2-30t+24=0 ?

The solutions to the equation 3t^2-30t+24=0 are t=5+sqrt(17),t=5-sqrt(17)

Find the zeros of 3t^2-30t+24=0

The zeros of 3t^2-30t+24=0 are t=5+sqrt(17),t=5-sqrt(17)

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3 t^{2} - 30 t + 24 = 0

t = 5 + 17, t = 5 - 17

Decimal Notation

t = 9.12310 \dots, t = 0.87689 \dots

Solution steps

3 t^{2} - 30 t + 24 = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- ( - 30 ) \pm ( - 30 ) ^{2} - 4 \cdot 3 \cdot 24}{2 \cdot 3}

(- 30)^{2} - 4 \cdot 3 \cdot 24 = 617

t_{1, 2} = \frac{- ( - 30 ) \pm 6 17}{2 \cdot 3}

Separate the solutions

t_{1} = \frac{- ( - 30 ) + 6 17}{2 \cdot 3}, t_{2} = \frac{- ( - 30 ) - 6 17}{2 \cdot 3}

t = \frac{- ( - 30 ) + 6 17}{2 \cdot 3} : 5 + 17

t = \frac{- ( - 30 ) - 6 17}{2 \cdot 3} : 5 - 17

The solutions to the quadratic equation are:

t = 5 + 17, t = 5 - 17

x^{2} - 11 x + 16 = 0

h^{2} = 1^{2} + 1^{2}

x, (x y + 3)^{2} + (x + y)^{2} = 8

\frac{1}{5} x^{2} = 4

x, 3 e^{4 y + 8} = 6 x^{2} - 2

What are the solutions to the equation 3t^2-30t+24=0 ?
The solutions to the equation 3t^2-30t+24=0 are t=5+sqrt(17),t=5-sqrt(17)
Find the zeros of 3t^2-30t+24=0
The zeros of 3t^2-30t+24=0 are t=5+sqrt(17),t=5-sqrt(17)