What are the solutions to the equation x^2-3x+54=0 ?

The solutions to the equation x^2-3x+54=0 are x= 3/2+i(3sqrt(23))/2 ,x= 3/2-i(3sqrt(23))/2

Find the zeros of x^2-3x+54=0

The zeros of x^2-3x+54=0 are x= 3/2+i(3sqrt(23))/2 ,x= 3/2-i(3sqrt(23))/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^{2} - 3 x + 54 = 0

x = \frac{3}{2} + i \frac{3 23}{2}, x = \frac{3}{2} - i \frac{3 23}{2}

Solution steps

x^{2} - 3 x + 54 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 \cdot 1 \cdot 54}{2 \cdot 1}

Simplify

(- 3)^{2} - 4 \cdot 1 \cdot 54 : 323 i

x_{1, 2} = \frac{- ( - 3 ) \pm 3 23 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 3 ) + 3 23 i}{2 \cdot 1}, x_{2} = \frac{- ( - 3 ) - 3 23 i}{2 \cdot 1}

x = \frac{- ( - 3 ) + 3 23 i}{2 \cdot 1} : \frac{3}{2} + i \frac{3 23}{2}

x = \frac{- ( - 3 ) - 3 23 i}{2 \cdot 1} : \frac{3}{2} - i \frac{3 23}{2}

The solutions to the quadratic equation are:

x = \frac{3}{2} + i \frac{3 23}{2}, x = \frac{3}{2} - i \frac{3 23}{2}

t, r (t) = a \frac{t ^{2}}{2}

y^{2} = 1 5^{2} - 9^{2}

4 x^{2} - 3 - 4 x = 0

y, 2 x^{2} = y^{2}

x^{2} + 1 0^{- 7} \cdot x - 3.23 \cdot 1 0^{- 4} = 0

What are the solutions to the equation x^2-3x+54=0 ?
The solutions to the equation x^2-3x+54=0 are x= 3/2+i(3sqrt(23))/2 ,x= 3/2-i(3sqrt(23))/2
Find the zeros of x^2-3x+54=0
The zeros of x^2-3x+54=0 are x= 3/2+i(3sqrt(23))/2 ,x= 3/2-i(3sqrt(23))/2