What are the solutions to the equation 4x^2-3-4x=0 ?

The solutions to the equation 4x^2-3-4x=0 are x= 3/2 ,x=-1/2

Find the zeros of 4x^2-3-4x=0

The zeros of 4x^2-3-4x=0 are x= 3/2 ,x=-1/2

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4 x^{2} - 3 - 4 x = 0

x = \frac{3}{2}, x = - \frac{1}{2}

Decimal Notation

x = 1.5, x = - 0.5

Solution steps

4 x^{2} - 3 - 4 x = 0

Write in the standard form

a x^{2} + b x + c = 0

4 x^{2} - 4 x - 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 4 ( - 3 )}{2 \cdot 4}

(- 4)^{2} - 4 \cdot 4 (- 3) = 8

x_{1, 2} = \frac{- ( - 4 ) \pm 8}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 8}{2 \cdot 4}, x_{2} = \frac{- ( - 4 ) - 8}{2 \cdot 4}

x = \frac{- ( - 4 ) + 8}{2 \cdot 4} : \frac{3}{2}

x = \frac{- ( - 4 ) - 8}{2 \cdot 4} : - \frac{1}{2}

The solutions to the quadratic equation are:

x = \frac{3}{2}, x = - \frac{1}{2}

y, 2 x^{2} = y^{2}

x^{2} + 1 0^{- 7} \cdot x - 3.23 \cdot 1 0^{- 4} = 0

0 = 9 x^{2} + 12 x + 4

\frac{200 \cdot 1 0 ^{3}}{33.728 \cdot 1 0 ^{6}} = 2 x^{2}

5 x^{2} - 8 = 37

What are the solutions to the equation 4x^2-3-4x=0 ?
The solutions to the equation 4x^2-3-4x=0 are x= 3/2 ,x=-1/2
Find the zeros of 4x^2-3-4x=0
The zeros of 4x^2-3-4x=0 are x= 3/2 ,x=-1/2