What are the solutions to the equation 0=9x^2+12x+4 ?

The solutions to the equation 0=9x^2+12x+4 are x=-2/3

Find the zeros of 0=9x^2+12x+4

The zeros of 0=9x^2+12x+4 are x=-2/3

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0 = 9 x^{2} + 12 x + 4

x = - \frac{2}{3}

Decimal Notation

x = - 0.66666 \dots

Solution steps

0 = 9 x^{2} + 12 x + 4

Switch sides

9 x^{2} + 12 x + 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 12 \pm 1 2 ^{2} - 4 \cdot 9 \cdot 4}{2 \cdot 9}

1 2^{2} - 4 \cdot 9 \cdot 4 = 0

x_{1, 2} = \frac{- 12 \pm 0}{2 \cdot 9}

x = \frac{- 12}{2 \cdot 9}

\frac{- 12}{2 \cdot 9} = - \frac{2}{3}

x = - \frac{2}{3}

The solution to the quadratic equation is:

x = - \frac{2}{3}

\frac{200 \cdot 1 0 ^{3}}{33.728 \cdot 1 0 ^{6}} = 2 x^{2}

5 x^{2} - 8 = 37

0 = x^{2} + 5 x + 1

(117 - x) (333 - x) - 8 1^{2} = 0

x, (2 x - 1)^{2} = 9 (y^{2} + z^{2})

What are the solutions to the equation 0=9x^2+12x+4 ?
The solutions to the equation 0=9x^2+12x+4 are x=-2/3
Find the zeros of 0=9x^2+12x+4
The zeros of 0=9x^2+12x+4 are x=-2/3