What are the solutions to the equation solvefor x,x^2+x=6 ?

The solutions to the equation solvefor x,x^2+x=6 are x=2,x=-3

Find the zeros of solvefor x,x^2+x=6

The zeros of solvefor x,x^2+x=6 are x=2,x=-3

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x, x^{2} + x = 6

x = 2, x = - 3

Solution steps

x^{2} + x = 6

Move

6

to the left side

x^{2} + x - 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 1 \cdot ( - 6 )}{2 \cdot 1}

1^{2} - 4 \cdot 1 \cdot (- 6) = 5

x_{1, 2} = \frac{- 1 \pm 5}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 1 + 5}{2 \cdot 1}, x_{2} = \frac{- 1 - 5}{2 \cdot 1}

x = \frac{- 1 + 5}{2 \cdot 1} : 2

x = \frac{- 1 - 5}{2 \cdot 1} : - 3

The solutions to the quadratic equation are:

x = 2, x = - 3

r^{2} - 10 r + 9 = 0

x (x - 4) = 60

(x - 3) (x - 2) = 6 x - 18

4 x^{2} - 2523 x + 29485 = 41 x^{2} + 83 x - 1083

938 = \frac{x ^{2} \cdot 0.262 \cdot ( 1 - 0.262 )}{0.03 7 ^{2}}

What are the solutions to the equation solvefor x,x^2+x=6 ?
The solutions to the equation solvefor x,x^2+x=6 are x=2,x=-3
Find the zeros of solvefor x,x^2+x=6
The zeros of solvefor x,x^2+x=6 are x=2,x=-3