What are the solutions to the equation (x-3)(x-2)=6x-18 ?

The solutions to the equation (x-3)(x-2)=6x-18 are x=8,x=3

Find the zeros of (x-3)(x-2)=6x-18

The zeros of (x-3)(x-2)=6x-18 are x=8,x=3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(x - 3) (x - 2) = 6 x - 18

x = 8, x = 3

Solution steps

(x - 3) (x - 2) = 6 x - 18

Expand

(x - 3) (x - 2) : x^{2} - 5 x + 6

x^{2} - 5 x + 6 = 6 x - 18

Move

18

to the left side

x^{2} - 5 x + 24 = 6 x

Move

6 x

to the left side

x^{2} - 11 x + 24 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 11 ) \pm ( - 11 ) ^{2} - 4 \cdot 1 \cdot 24}{2 \cdot 1}

(- 11)^{2} - 4 \cdot 1 \cdot 24 = 5

x_{1, 2} = \frac{- ( - 11 ) \pm 5}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 11 ) + 5}{2 \cdot 1}, x_{2} = \frac{- ( - 11 ) - 5}{2 \cdot 1}

x = \frac{- ( - 11 ) + 5}{2 \cdot 1} : 8

x = \frac{- ( - 11 ) - 5}{2 \cdot 1} : 3

The solutions to the quadratic equation are:

x = 8, x = 3

4 x^{2} - 2523 x + 29485 = 41 x^{2} + 83 x - 1083

938 = \frac{x ^{2} \cdot 0.262 \cdot ( 1 - 0.262 )}{0.03 7 ^{2}}

\frac{5}{4} x + 5 = x^{2} + \frac{5}{4} x - 11

4.9 x^{2} + 330 x - 1650 = 0

24000 = - \frac{1}{30} x^{2} + \frac{4}{5} x + 30

What are the solutions to the equation (x-3)(x-2)=6x-18 ?
The solutions to the equation (x-3)(x-2)=6x-18 are x=8,x=3
Find the zeros of (x-3)(x-2)=6x-18
The zeros of (x-3)(x-2)=6x-18 are x=8,x=3