What are the solutions to the equation 5/4 x+5=x^2+5/4 x-11 ?

The solutions to the equation 5/4 x+5=x^2+5/4 x-11 are x=4,x=-4

Find the zeros of 5/4 x+5=x^2+5/4 x-11

The zeros of 5/4 x+5=x^2+5/4 x-11 are x=4,x=-4

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\frac{5}{4} x + 5 = x^{2} + \frac{5}{4} x - 11

x = 4, x = - 4

Solution steps

\frac{5}{4} x + 5 = x^{2} + \frac{5}{4} x - 11

Switch sides

x^{2} + \frac{5}{4} x - 11 = \frac{5}{4} x + 5

Move

11

to the right side

x^{2} + \frac{5}{4} x = \frac{5}{4} x + 16

Move

\frac{5}{4} x

to the left side

x^{2} = 16

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 16, x = - 16

16 = 4

- 16 = - 4

x = 4, x = - 4

4.9 x^{2} + 330 x - 1650 = 0

24000 = - \frac{1}{30} x^{2} + \frac{4}{5} x + 30

- 16 t^{2} + 25 = 0

3 x^{2} + 6 x + 1 = 0

- 2 x^{2} - 9 x - 5 = 0

What are the solutions to the equation 5/4 x+5=x^2+5/4 x-11 ?
The solutions to the equation 5/4 x+5=x^2+5/4 x-11 are x=4,x=-4
Find the zeros of 5/4 x+5=x^2+5/4 x-11
The zeros of 5/4 x+5=x^2+5/4 x-11 are x=4,x=-4