What are the solutions to the equation completesquare 3x^2+6x+1=0 ?

The solutions to the equation completesquare 3x^2+6x+1=0 are x=sqrt(2/3)-1,x=-sqrt(2/3)-1

Find the zeros of completesquare 3x^2+6x+1=0

The zeros of completesquare 3x^2+6x+1=0 are x=sqrt(2/3)-1,x=-sqrt(2/3)-1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

3 x^{2} + 6 x + 1 = 0

x = \frac{2}{3} - 1, x = - \frac{2}{3} - 1

Decimal Notation

x = - 0.18350 \dots, x = - 1.81649 \dots

Solution steps

3 x^{2} + 6 x + 1 = 0

Move

1

to the right side

3 x^{2} + 6 x = - 1

Divide both sides by

3

\frac{3 x ^{2} + 6 x}{3} = \frac{- 1}{3}

x^{2} + 2 x = - \frac{1}{3}

Rewrite in the form

(x + a)^{2} = b

(x + 1)^{2} = \frac{2}{3}

For

the solutions are

f (x) = a, - a

Solve

x + 1 = \frac{2}{3} : x = \frac{2}{3} - 1

Solve

x + 1 = - \frac{2}{3} : x = - \frac{2}{3} - 1

The solutions to the quadratic equation are:

x = \frac{2}{3} - 1, x = - \frac{2}{3} - 1

- 2 x^{2} - 9 x - 5 = 0

x, h^{2} = x^{2} + 2 y^{2}

4 x^{2} + a^{2} = 4 a x + b^{2}

x^{2} - 10 x - 66 = 0

x^{2} + 5 x - 2 = 0

What are the solutions to the equation completesquare 3x^2+6x+1=0 ?
The solutions to the equation completesquare 3x^2+6x+1=0 are x=sqrt(2/3)-1,x=-sqrt(2/3)-1
Find the zeros of completesquare 3x^2+6x+1=0
The zeros of completesquare 3x^2+6x+1=0 are x=sqrt(2/3)-1,x=-sqrt(2/3)-1