What are the solutions to the equation 5x^2+9x-9=0 ?

The solutions to the equation 5x^2+9x-9=0 are x=(-9+3sqrt(29))/(10),x=(-9-3sqrt(29))/(10)

Find the zeros of 5x^2+9x-9=0

The zeros of 5x^2+9x-9=0 are x=(-9+3sqrt(29))/(10),x=(-9-3sqrt(29))/(10)

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5 x^{2} + 9 x - 9 = 0

x = \frac{- 9 + 3 29}{10}, x = \frac{- 9 - 3 29}{10}

Decimal Notation

x = 0.71554 \dots, x = - 2.51554 \dots

Solution steps

5 x^{2} + 9 x - 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 9 \pm 9 ^{2} - 4 \cdot 5 ( - 9 )}{2 \cdot 5}

9^{2} - 4 \cdot 5 (- 9) = 329

x_{1, 2} = \frac{- 9 \pm 3 29}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- 9 + 3 29}{2 \cdot 5}, x_{2} = \frac{- 9 - 3 29}{2 \cdot 5}

x = \frac{- 9 + 3 29}{2 \cdot 5} : \frac{- 9 + 3 29}{10}

x = \frac{- 9 - 3 29}{2 \cdot 5} : \frac{- 9 - 3 29}{10}

The solutions to the quadratic equation are:

x = \frac{- 9 + 3 29}{10}, x = \frac{- 9 - 3 29}{10}

35 x^{2} + 9 x - 2 = 0

- 4 x^{2} - 32 x = 0

3 y^{2} + y - 4 = 0

1 1^{2} + 6^{2} = c^{2}

\frac{3 x ^{2}}{8} = 0

What are the solutions to the equation 5x^2+9x-9=0 ?
The solutions to the equation 5x^2+9x-9=0 are x=(-9+3sqrt(29))/(10),x=(-9-3sqrt(29))/(10)
Find the zeros of 5x^2+9x-9=0
The zeros of 5x^2+9x-9=0 are x=(-9+3sqrt(29))/(10),x=(-9-3sqrt(29))/(10)