What are the solutions to the equation 0=8x-2x^2 ?

The solutions to the equation 0=8x-2x^2 are x=0,x=4

Find the zeros of 0=8x-2x^2

The zeros of 0=8x-2x^2 are x=0,x=4

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0 = 8 x - 2 x^{2}

x = 0, x = 4

Solution steps

0 = 8 x - 2 x^{2}

Switch sides

8 x - 2 x^{2} = 0

Write in the standard form

a x^{2} + b x + c = 0

- 2 x^{2} + 8 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 ( - 2 ) \cdot 0}{2 ( - 2 )}

8^{2} - 4 (- 2) \cdot 0 = 8

x_{1, 2} = \frac{- 8 \pm 8}{2 ( - 2 )}

Separate the solutions

x_{1} = \frac{- 8 + 8}{2 ( - 2 )}, x_{2} = \frac{- 8 - 8}{2 ( - 2 )}

x = \frac{- 8 + 8}{2 ( - 2 )} : 0

x = \frac{- 8 - 8}{2 ( - 2 )} : 4

The solutions to the quadratic equation are:

x = 0, x = 4

(x - 5)^{2} - 25 = 0

2 x^{2} = 28 - 10 x

x, 2 x^{2} - 7 x + 5 = 0

4 + q = 16 - q^{2}

g^{2} + 4 g - 32 = 0

What are the solutions to the equation 0=8x-2x^2 ?
The solutions to the equation 0=8x-2x^2 are x=0,x=4
Find the zeros of 0=8x-2x^2
The zeros of 0=8x-2x^2 are x=0,x=4