What are the solutions to the equation solvefor x,2x^2-7x+5=0 ?

The solutions to the equation solvefor x,2x^2-7x+5=0 are x= 5/2 ,x=1

Find the zeros of solvefor x,2x^2-7x+5=0

The zeros of solvefor x,2x^2-7x+5=0 are x= 5/2 ,x=1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x, 2 x^{2} - 7 x + 5 = 0

x = \frac{5}{2}, x = 1

Decimal Notation

x = 2.5, x = 1

Solution steps

2 x^{2} - 7 x + 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 7 ) \pm ( - 7 ) ^{2} - 4 \cdot 2 \cdot 5}{2 \cdot 2}

(- 7)^{2} - 4 \cdot 2 \cdot 5 = 3

x_{1, 2} = \frac{- ( - 7 ) \pm 3}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 7 ) + 3}{2 \cdot 2}, x_{2} = \frac{- ( - 7 ) - 3}{2 \cdot 2}

x = \frac{- ( - 7 ) + 3}{2 \cdot 2} : \frac{5}{2}

x = \frac{- ( - 7 ) - 3}{2 \cdot 2} : 1

The solutions to the quadratic equation are:

x = \frac{5}{2}, x = 1

4 + q = 16 - q^{2}

g^{2} + 4 g - 32 = 0

x, x^{2} + 2 x = 3

x^{2} - 25 x + 4 = 0

- x^{2} + 120 x - 2975 = 0

What are the solutions to the equation solvefor x,2x^2-7x+5=0 ?
The solutions to the equation solvefor x,2x^2-7x+5=0 are x= 5/2 ,x=1
Find the zeros of solvefor x,2x^2-7x+5=0
The zeros of solvefor x,2x^2-7x+5=0 are x= 5/2 ,x=1