What are the solutions to the equation -x^2+120x-2975=0 ?

The solutions to the equation -x^2+120x-2975=0 are x=35,x=85

Find the zeros of -x^2+120x-2975=0

The zeros of -x^2+120x-2975=0 are x=35,x=85

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- x^{2} + 120 x - 2975 = 0

x = 35, x = 85

Solution steps

- x^{2} + 120 x - 2975 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 120 \pm 12 0 ^{2} - 4 ( - 1 ) ( - 2975 )}{2 ( - 1 )}

12 0^{2} - 4 (- 1) (- 2975) = 50

x_{1, 2} = \frac{- 120 \pm 50}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- 120 + 50}{2 ( - 1 )}, x_{2} = \frac{- 120 - 50}{2 ( - 1 )}

x = \frac{- 120 + 50}{2 ( - 1 )} : 35

x = \frac{- 120 - 50}{2 ( - 1 )} : 85

The solutions to the quadratic equation are:

x = 35, x = 85

5 n^{2} + 2 n - 8 = 0

(x^{2} - 3 x + 9) = 0

x, d = \frac{1}{3} x^{2} t

63.97 d^{2} + 20.626 d - 37.02 = 0

x^{2} + (x - 2)^{2} = 164

What are the solutions to the equation -x^2+120x-2975=0 ?
The solutions to the equation -x^2+120x-2975=0 are x=35,x=85
Find the zeros of -x^2+120x-2975=0
The zeros of -x^2+120x-2975=0 are x=35,x=85