What are the solutions to the equation (x^2-3x+9)=0 ?

The solutions to the equation (x^2-3x+9)=0 are x= 3/2+i(3sqrt(3))/2 ,x= 3/2-i(3sqrt(3))/2

Find the zeros of (x^2-3x+9)=0

The zeros of (x^2-3x+9)=0 are x= 3/2+i(3sqrt(3))/2 ,x= 3/2-i(3sqrt(3))/2

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(x^{2} - 3 x + 9) = 0

x = \frac{3}{2} + i \frac{3 3}{2}, x = \frac{3}{2} - i \frac{3 3}{2}

Solution steps

(x^{2} - 3 x + 9) = 0

Refine

x^{2} - 3 x + 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 \cdot 1 \cdot 9}{2 \cdot 1}

Simplify

(- 3)^{2} - 4 \cdot 1 \cdot 9 : 33 i

x_{1, 2} = \frac{- ( - 3 ) \pm 3 3 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 3 ) + 3 3 i}{2 \cdot 1}, x_{2} = \frac{- ( - 3 ) - 3 3 i}{2 \cdot 1}

x = \frac{- ( - 3 ) + 3 3 i}{2 \cdot 1} : \frac{3}{2} + i \frac{3 3}{2}

x = \frac{- ( - 3 ) - 3 3 i}{2 \cdot 1} : \frac{3}{2} - i \frac{3 3}{2}

The solutions to the quadratic equation are:

x = \frac{3}{2} + i \frac{3 3}{2}, x = \frac{3}{2} - i \frac{3 3}{2}

x, d = \frac{1}{3} x^{2} t

63.97 d^{2} + 20.626 d - 37.02 = 0

x^{2} + (x - 2)^{2} = 164

5.3 \cdot 1 0^{- 12} = (1 \cdot 1 0^{- 4} + s) (s)

16 t^{2} - 150 = 0

What are the solutions to the equation (x^2-3x+9)=0 ?
The solutions to the equation (x^2-3x+9)=0 are x= 3/2+i(3sqrt(3))/2 ,x= 3/2-i(3sqrt(3))/2
Find the zeros of (x^2-3x+9)=0
The zeros of (x^2-3x+9)=0 are x= 3/2+i(3sqrt(3))/2 ,x= 3/2-i(3sqrt(3))/2