What are the solutions to the equation x^2+(x-2)^2=164 ?

The solutions to the equation x^2+(x-2)^2=164 are x=10,x=-8

Find the zeros of x^2+(x-2)^2=164

The zeros of x^2+(x-2)^2=164 are x=10,x=-8

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x^{2} + (x - 2)^{2} = 164

x = 10, x = - 8

Solution steps

x^{2} + (x - 2)^{2} = 164

Expand

x^{2} + (x - 2)^{2} : 2 x^{2} - 4 x + 4

2 x^{2} - 4 x + 4 = 164

Move

164

to the left side

2 x^{2} - 4 x - 160 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 2 ( - 160 )}{2 \cdot 2}

(- 4)^{2} - 4 \cdot 2 (- 160) = 36

x_{1, 2} = \frac{- ( - 4 ) \pm 36}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 36}{2 \cdot 2}, x_{2} = \frac{- ( - 4 ) - 36}{2 \cdot 2}

x = \frac{- ( - 4 ) + 36}{2 \cdot 2} : 10

x = \frac{- ( - 4 ) - 36}{2 \cdot 2} : - 8

The solutions to the quadratic equation are:

x = 10, x = - 8

5.3 \cdot 1 0^{- 12} = (1 \cdot 1 0^{- 4} + s) (s)

16 t^{2} - 150 = 0

x^{2} + x = 9

(x - 15)^{2} = 0

x, x^{2} y - 4 y = 8

What are the solutions to the equation x^2+(x-2)^2=164 ?
The solutions to the equation x^2+(x-2)^2=164 are x=10,x=-8
Find the zeros of x^2+(x-2)^2=164
The zeros of x^2+(x-2)^2=164 are x=10,x=-8