What are the solutions to the equation quadraticformula x^2+x=9 ?

The solutions to the equation quadraticformula x^2+x=9 are x=(-1+sqrt(37))/2 ,x=(-1-sqrt(37))/2

Find the zeros of quadraticformula x^2+x=9

The zeros of quadraticformula x^2+x=9 are x=(-1+sqrt(37))/2 ,x=(-1-sqrt(37))/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^{2} + x = 9

x = \frac{- 1 + 37}{2}, x = \frac{- 1 - 37}{2}

Decimal Notation

x = 2.54138 \dots, x = - 3.54138 \dots

Solution steps

x^{2} + x = 9

Move

9

to the left side

x^{2} + x - 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 1 \cdot ( - 9 )}{2 \cdot 1}

1^{2} - 4 \cdot 1 \cdot (- 9) = 37

x_{1, 2} = \frac{- 1 \pm 37}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 1 + 37}{2 \cdot 1}, x_{2} = \frac{- 1 - 37}{2 \cdot 1}

x = \frac{- 1 + 37}{2 \cdot 1} : \frac{- 1 + 37}{2}

x = \frac{- 1 - 37}{2 \cdot 1} : \frac{- 1 - 37}{2}

The solutions to the quadratic equation are:

x = \frac{- 1 + 37}{2}, x = \frac{- 1 - 37}{2}

(x - 15)^{2} = 0

x, x^{2} y - 4 y = 8

B, rs = ro + \frac{B}{s} (ro - r B) (1 - T c)

2 \cdot ((30 - 2 x) x + (20 - 2 x) x) = 200

x^{2} - 18 x = 7

What are the solutions to the equation quadraticformula x^2+x=9 ?
The solutions to the equation quadraticformula x^2+x=9 are x=(-1+sqrt(37))/2 ,x=(-1-sqrt(37))/2
Find the zeros of quadraticformula x^2+x=9
The zeros of quadraticformula x^2+x=9 are x=(-1+sqrt(37))/2 ,x=(-1-sqrt(37))/2