What are the solutions to the equation 2*((30-2x)x+(20-2x)x)=200 ?

The solutions to the equation 2*((30-2x)x+(20-2x)x)=200 are x= 5/2 ,x=10

Find the zeros of 2*((30-2x)x+(20-2x)x)=200

The zeros of 2*((30-2x)x+(20-2x)x)=200 are x= 5/2 ,x=10

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2 \cdot ((30 - 2 x) x + (20 - 2 x) x) = 200

x = \frac{5}{2}, x = 10

Decimal Notation

x = 2.5, x = 10

Solution steps

2 ((30 - 2 x) x + (20 - 2 x) x) = 200

Expand

2 ((30 - 2 x) x + (20 - 2 x) x) : - 8 x^{2} + 100 x

- 8 x^{2} + 100 x = 200

Move

200

to the left side

- 8 x^{2} + 100 x - 200 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 100 \pm 10 0 ^{2} - 4 ( - 8 ) ( - 200 )}{2 ( - 8 )}

10 0^{2} - 4 (- 8) (- 200) = 60

x_{1, 2} = \frac{- 100 \pm 60}{2 ( - 8 )}

Separate the solutions

x_{1} = \frac{- 100 + 60}{2 ( - 8 )}, x_{2} = \frac{- 100 - 60}{2 ( - 8 )}

x = \frac{- 100 + 60}{2 ( - 8 )} : \frac{5}{2}

x = \frac{- 100 - 60}{2 ( - 8 )} : 10

The solutions to the quadratic equation are:

x = \frac{5}{2}, x = 10

x^{2} - 18 x = 7

x^{2} - 18 x = 6

y, y^{2} = x (3 - x)^{2}

- 5 (x - 3) + 2 = \frac{1}{2} x (x - 2)

x^{2} - 2 x + 1 = x + 1

What are the solutions to the equation 2*((30-2x)x+(20-2x)x)=200 ?
The solutions to the equation 2*((30-2x)x+(20-2x)x)=200 are x= 5/2 ,x=10
Find the zeros of 2*((30-2x)x+(20-2x)x)=200
The zeros of 2*((30-2x)x+(20-2x)x)=200 are x= 5/2 ,x=10