What are the solutions to the equation 2m^2-5m=0 ?

The solutions to the equation 2m^2-5m=0 are m= 5/2 ,m=0

Find the zeros of 2m^2-5m=0

The zeros of 2m^2-5m=0 are m= 5/2 ,m=0

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2 m^{2} - 5 m = 0

m = \frac{5}{2}, m = 0

Decimal Notation

m = 2.5, m = 0

Solution steps

2 m^{2} - 5 m = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 2 \cdot 0}{2 \cdot 2}

(- 5)^{2} - 4 \cdot 2 \cdot 0 = 5

m_{1, 2} = \frac{- ( - 5 ) \pm 5}{2 \cdot 2}

Separate the solutions

m_{1} = \frac{- ( - 5 ) + 5}{2 \cdot 2}, m_{2} = \frac{- ( - 5 ) - 5}{2 \cdot 2}

m = \frac{- ( - 5 ) + 5}{2 \cdot 2} : \frac{5}{2}

m = \frac{- ( - 5 ) - 5}{2 \cdot 2} : 0

The solutions to the quadratic equation are:

m = \frac{5}{2}, m = 0

x, y = x^{2} - 5 x

30 x - 0.1 x^{2} = 1890, 0 \leq x \leq 150

0 = 7 x^{2} - 31 - 20

Y, Y^{2} - Y = X^{3} - X

x^{2} - 22 x + 105 = 0

What are the solutions to the equation 2m^2-5m=0 ?
The solutions to the equation 2m^2-5m=0 are m= 5/2 ,m=0
Find the zeros of 2m^2-5m=0
The zeros of 2m^2-5m=0 are m= 5/2 ,m=0