What are the solutions to the equation 0=7x^2-31-20 ?

The solutions to the equation 0=7x^2-31-20 are x=sqrt(51/7),x=-sqrt(51/7)

Find the zeros of 0=7x^2-31-20

The zeros of 0=7x^2-31-20 are x=sqrt(51/7),x=-sqrt(51/7)

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0 = 7 x^{2} - 31 - 20

x = \frac{51}{7}, x = - \frac{51}{7}

Decimal

x = 2.69920 \dots, x = - 2.69920 \dots

Solution steps

0 = 7 x^{2} - 31 - 20

Switch sides

7 x^{2} - 31 - 20 = 0

Move

31

to the right side

7 x^{2} - 20 = 31

Move

20

to the right side

7 x^{2} = 51

Divide both sides by

7

x^{2} = \frac{51}{7}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{51}{7}, x = - \frac{51}{7}

Y, Y^{2} - Y = X^{3} - X

x^{2} - 22 x + 105 = 0

x, 6 x^{2} + 18 y^{2} + 36 y + 4 x + 56 = 0

(2 x - 1)^{2} - 4 = 0

4 x^{2} - 29 x - 24 = 0

What are the solutions to the equation 0=7x^2-31-20 ?
The solutions to the equation 0=7x^2-31-20 are x=sqrt(51/7),x=-sqrt(51/7)
Find the zeros of 0=7x^2-31-20
The zeros of 0=7x^2-31-20 are x=sqrt(51/7),x=-sqrt(51/7)