What are the solutions to the equation 15x=x^2-16 ?

The solutions to the equation 15x=x^2-16 are x=16,x=-1

Find the zeros of 15x=x^2-16

The zeros of 15x=x^2-16 are x=16,x=-1

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15 x = x^{2} - 16

x = 16, x = - 1

Solution steps

15 x = x^{2} - 16

Switch sides

x^{2} - 16 = 15 x

Move

15 x

to the left side

x^{2} - 16 - 15 x = 0

Write in the standard form

a x^{2} + b x + c = 0

x^{2} - 15 x - 16 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 15 ) \pm ( - 15 ) ^{2} - 4 \cdot 1 \cdot ( - 16 )}{2 \cdot 1}

(- 15)^{2} - 4 \cdot 1 \cdot (- 16) = 17

x_{1, 2} = \frac{- ( - 15 ) \pm 17}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 15 ) + 17}{2 \cdot 1}, x_{2} = \frac{- ( - 15 ) - 17}{2 \cdot 1}

x = \frac{- ( - 15 ) + 17}{2 \cdot 1} : 16

x = \frac{- ( - 15 ) - 17}{2 \cdot 1} : - 1

The solutions to the quadratic equation are:

x = 16, x = - 1

0 = - \frac{1}{2} (x - 2)^{2} + 8

- 0.000003 x^{2} + 0.003 x + 6 = 0

7 x^{2} + 13 x + 6 = 0

2 x^{2} - 11 x + 5 = 0

x, y = 3 x^{2} - 1

What are the solutions to the equation 15x=x^2-16 ?
The solutions to the equation 15x=x^2-16 are x=16,x=-1
Find the zeros of 15x=x^2-16
The zeros of 15x=x^2-16 are x=16,x=-1