What are the solutions to the equation 0=-1/2 (x-2)^2+8 ?

The solutions to the equation 0=-1/2 (x-2)^2+8 are x=6,x=-2

Find the zeros of 0=-1/2 (x-2)^2+8

The zeros of 0=-1/2 (x-2)^2+8 are x=6,x=-2

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0 = - \frac{1}{2} (x - 2)^{2} + 8

x = 6, x = - 2

Solution steps

0 = - \frac{1}{2} (x - 2)^{2} + 8

Switch sides

- \frac{1}{2} (x - 2)^{2} + 8 = 0

Move

8

to the right side

- \frac{1}{2} (x - 2)^{2} = - 8

Multiply both sides by

- 2

(x - 2)^{2} = 16

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 2 = 16 : x = 6

Solve

x - 2 = - 16 : x = - 2

The solutions to the quadratic equation are:

x = 6, x = - 2

- 0.000003 x^{2} + 0.003 x + 6 = 0

7 x^{2} + 13 x + 6 = 0

2 x^{2} - 11 x + 5 = 0

x, y = 3 x^{2} - 1

9 y^{2} = 3 (3 - 3) 2

What are the solutions to the equation 0=-1/2 (x-2)^2+8 ?
The solutions to the equation 0=-1/2 (x-2)^2+8 are x=6,x=-2
Find the zeros of 0=-1/2 (x-2)^2+8
The zeros of 0=-1/2 (x-2)^2+8 are x=6,x=-2