What are the solutions to the equation 9y^2=3(3-3)2 ?

The solutions to the equation 9y^2=3(3-3)2 are y=0

Find the zeros of 9y^2=3(3-3)2

The zeros of 9y^2=3(3-3)2 are y=0

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9 y^{2} = 3 (3 - 3) 2

y = 0

Solution steps

9 y^{2} = 3 (3 - 3) \cdot 2

Subtract the numbers:

3 - 3 = 0

9 y^{2} = 3 \cdot 0 \cdot 2

Apply rule

0 \cdot a = 0

9 y^{2} = 0

Divide both sides by

9

y = 0

0.05 x^{2} + 2 x + 100 = 0

(x^{2} - 81) = 0

2 (3 x + 5) + 2 (x - 5) = 2 (3 x + 5) (x - 5)

x^{2} + 9 x + 15 = 0

2 5^{2} - 7^{2} = x^{2}

What are the solutions to the equation 9y^2=3(3-3)2 ?
The solutions to the equation 9y^2=3(3-3)2 are y=0
Find the zeros of 9y^2=3(3-3)2
The zeros of 9y^2=3(3-3)2 are y=0