What are the solutions to the equation 28090=25000(1+x)^2 ?

The solutions to the equation 28090=25000(1+x)^2 are x= 3/50 ,x=-103/50

Find the zeros of 28090=25000(1+x)^2

The zeros of 28090=25000(1+x)^2 are x= 3/50 ,x=-103/50

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28090 = 25000 (1 + x)^{2}

x = \frac{3}{50}, x = - \frac{103}{50}

Decimal Notation

x = 0.06, x = - 2.06

Solution steps

28090 = 25000 (1 + x)^{2}

Switch sides

25000 (1 + x)^{2} = 28090

Divide both sides by

25000

(1 + x)^{2} = \frac{2809}{2500}

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

1 + x = \frac{2809}{2500} : x = \frac{3}{50}

Solve

1 + x = - \frac{2809}{2500} : x = - \frac{103}{50}

The solutions to the quadratic equation are:

x = \frac{3}{50}, x = - \frac{103}{50}

\frac{- t ^{2}}{4} + 400 = 39

(x - 7) (x + 4) = - 2

x, 3 x^{2} + 18 x - 3 y^{2} + 27 = 0

6 0^{2} + x^{2} = 6 1^{2}

2 x^{2} = 3 + 2 x

What are the solutions to the equation 28090=25000(1+x)^2 ?
The solutions to the equation 28090=25000(1+x)^2 are x= 3/50 ,x=-103/50
Find the zeros of 28090=25000(1+x)^2
The zeros of 28090=25000(1+x)^2 are x= 3/50 ,x=-103/50