What are the solutions to the equation solvefor x,3x^2+18x-3y^2+27=0 ?

The solutions to the equation solvefor x,3x^2+18x-3y^2+27=0 are x=-y-3,x=y-3

Find the zeros of solvefor x,3x^2+18x-3y^2+27=0

The zeros of solvefor x,3x^2+18x-3y^2+27=0 are x=-y-3,x=y-3

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solve for

x, 3 x^{2} + 18 x - 3 y^{2} + 27 = 0

x = - y - 3, x = y - 3

Solution steps

3 x^{2} + 18 x - 3 y^{2} + 27 = 0

Factor

3 x^{2} + 18 x - 3 y^{2} + 27 : 3 (x + y + 3) (x - y + 3)

3 (x + y + 3) (x - y + 3) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + y + 3 = 0 or x - y + 3 = 0

Solve

x + y + 3 = 0 : x = - y - 3

Solve

x - y + 3 = 0 : x = y - 3

The solutions to the quadratic equation are:

x = - y - 3, x = y - 3

6 0^{2} + x^{2} = 6 1^{2}

2 x^{2} = 3 + 2 x

6 x^{2} + 2 x - 2 = 0

z, ln (x^{2} + y^{2}) + 3^{x y} + z^{2} + z = 0

x^{2} + x = 240

What are the solutions to the equation solvefor x,3x^2+18x-3y^2+27=0 ?
The solutions to the equation solvefor x,3x^2+18x-3y^2+27=0 are x=-y-3,x=y-3
Find the zeros of solvefor x,3x^2+18x-3y^2+27=0
The zeros of solvefor x,3x^2+18x-3y^2+27=0 are x=-y-3,x=y-3