What are the solutions to the equation 1x^2+0x-4=0 ?

The solutions to the equation 1x^2+0x-4=0 are x=2,x=-2

Find the zeros of 1x^2+0x-4=0

The zeros of 1x^2+0x-4=0 are x=2,x=-2

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1 x^{2} + 0 x - 4 = 0

x = 2, x = - 2

Solution steps

1 \cdot x^{2} + 0 \cdot x - 4 = 0

Refine

x^{2} - 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 0 \pm 0 ^{2} - 4 \cdot 1 \cdot ( - 4 )}{2 \cdot 1}

0^{2} - 4 \cdot 1 \cdot (- 4) = 4

x_{1, 2} = \frac{- 0 \pm 4}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 0 + 4}{2 \cdot 1}, x_{2} = \frac{- 0 - 4}{2 \cdot 1}

x = \frac{- 0 + 4}{2 \cdot 1} : 2

x = \frac{- 0 - 4}{2 \cdot 1} : - 2

The solutions to the quadratic equation are:

x = 2, x = - 2

6 4^{2} = 2 x^{2}

(a - 2) (a - 4) = 0

11.13 X^{2} + 18.116 X - 16 = 0

x, f (x + 2) = x^{2}

a^{2} x^{2} - \frac{11}{6} a x - \frac{215}{144} = \frac{121}{144}

What are the solutions to the equation 1x^2+0x-4=0 ?
The solutions to the equation 1x^2+0x-4=0 are x=2,x=-2
Find the zeros of 1x^2+0x-4=0
The zeros of 1x^2+0x-4=0 are x=2,x=-2