What are the solutions to the equation x^2+x=0.1 ?

The solutions to the equation x^2+x=0.1 are x=(-5+sqrt(35))/(10),x=-(5+sqrt(35))/(10)

Find the zeros of x^2+x=0.1

The zeros of x^2+x=0.1 are x=(-5+sqrt(35))/(10),x=-(5+sqrt(35))/(10)

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x^{2} + x = 0.1

x = \frac{- 5 + 35}{10}, x = - \frac{5 + 35}{10}

Decimal Notation

x = 0.09160 \dots, x = - 1.09160 \dots

Solution steps

x^{2} + x = 0.1

Multiply both sides by

10

x^{2} \cdot 10 + x \cdot 10 = 1

Move

1

to the left side

x^{2} \cdot 10 + x \cdot 10 - 1 = 0

Write in the standard form

a x^{2} + b x + c = 0

10 x^{2} + 10 x - 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 \cdot 10 ( - 1 )}{2 \cdot 10}

1 0^{2} - 4 \cdot 10 (- 1) = 235

x_{1, 2} = \frac{- 10 \pm 2 35}{2 \cdot 10}

Separate the solutions

x_{1} = \frac{- 10 + 2 35}{2 \cdot 10}, x_{2} = \frac{- 10 - 2 35}{2 \cdot 10}

x = \frac{- 10 + 2 35}{2 \cdot 10} : \frac{- 5 + 35}{10}

x = \frac{- 10 - 2 35}{2 \cdot 10} : - \frac{5 + 35}{10}

The solutions to the quadratic equation are:

x = \frac{- 5 + 35}{10}, x = - \frac{5 + 35}{10}

x, x^{2} - 2 p x + p^{2} - q^{2} = 0

3 x^{2} + 4 x = 9

x^{2} + 18 x - 63 = 0

x^{2} + 5 = - 12

- y^{2} - 3 y

What are the solutions to the equation x^2+x=0.1 ?
The solutions to the equation x^2+x=0.1 are x=(-5+sqrt(35))/(10),x=-(5+sqrt(35))/(10)
Find the zeros of x^2+x=0.1
The zeros of x^2+x=0.1 are x=(-5+sqrt(35))/(10),x=-(5+sqrt(35))/(10)