What are the solutions to the equation z^2+6z-8=0 ?

The solutions to the equation z^2+6z-8=0 are z=-3+sqrt(17),z=-3-sqrt(17)

Find the zeros of z^2+6z-8=0

The zeros of z^2+6z-8=0 are z=-3+sqrt(17),z=-3-sqrt(17)

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z^{2} + 6 z - 8 = 0

z = - 3 + 17, z = - 3 - 17

Decimal Notation

z = 1.12310 \dots, z = - 7.12310 \dots

Solution steps

z^{2} + 6 z - 8 = 0

Solve with the quadratic formula

z_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 1 \cdot ( - 8 )}{2 \cdot 1}

6^{2} - 4 \cdot 1 \cdot (- 8) = 217

z_{1, 2} = \frac{- 6 \pm 2 17}{2 \cdot 1}

Separate the solutions

z_{1} = \frac{- 6 + 2 17}{2 \cdot 1}, z_{2} = \frac{- 6 - 2 17}{2 \cdot 1}

z = \frac{- 6 + 2 17}{2 \cdot 1} : - 3 + 17

z = \frac{- 6 - 2 17}{2 \cdot 1} : - 3 - 17

The solutions to the quadratic equation are:

z = - 3 + 17, z = - 3 - 17

74 - 2 x^{2} = 84

9 x^{2} - 5 x (\frac{28 x}{33}) + 7 (\frac{28 x}{33})^{2} = 120

(x + 5) x = 0

(x^{2} - 4 x + 4) - \frac{( 20 x + 8 ) ^{2}}{225} = 4

u, v (2 u v^{2} - 3) d u + (3 u^{2} v^{2} - 3 + 4 v) d v = 0

What are the solutions to the equation z^2+6z-8=0 ?
The solutions to the equation z^2+6z-8=0 are z=-3+sqrt(17),z=-3-sqrt(17)
Find the zeros of z^2+6z-8=0
The zeros of z^2+6z-8=0 are z=-3+sqrt(17),z=-3-sqrt(17)