What are the solutions to the equation (x+5)x=0 ?

The solutions to the equation (x+5)x=0 are x=-5,x=0

Find the zeros of (x+5)x=0

The zeros of (x+5)x=0 are x=-5,x=0

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(x + 5) x = 0

x = - 5, x = 0

Solution steps

(x + 5) x = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 5 = 0 or x = 0

Solve

x + 5 = 0 : x = - 5

The solutions to the quadratic equation are:

x = - 5, x = 0

(x^{2} - 4 x + 4) - \frac{( 20 x + 8 ) ^{2}}{225} = 4

u, v (2 u v^{2} - 3) d u + (3 u^{2} v^{2} - 3 + 4 v) d v = 0

a^{2} + 8 a - 9 = 0

4 n^{2} + 32 n + 64 = 0

5 x^{2} - 3 x - x = 0

What are the solutions to the equation (x+5)x=0 ?
The solutions to the equation (x+5)x=0 are x=-5,x=0
Find the zeros of (x+5)x=0
The zeros of (x+5)x=0 are x=-5,x=0