What are the solutions to the equation solvefor x,fx=x^2-4x ?

The solutions to the equation solvefor x,fx=x^2-4x are x=0,x=4+f

Find the zeros of solvefor x,fx=x^2-4x

The zeros of solvefor x,fx=x^2-4x are x=0,x=4+f

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solve for

x, f x = x^{2} - 4 x

x = 0, x = 4 + f

Solution steps

f x = x^{2} - 4 x

Switch sides

x^{2} - 4 x = f x

Move

f x

to the left side

x^{2} - 4 x - f x = 0

Write in the standard form

a x^{2} + b x + c = 0

x^{2} - (4 + f) x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 - f ) \pm ( - 4 - f ) ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

Simplify

(- 4 - f)^{2} - 4 \cdot 1 \cdot 0 : - f - 4

x_{1, 2} = \frac{- ( - 4 - f ) \pm ( - f - 4 )}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 4 - f ) - f - 4}{2 \cdot 1}, x_{2} = \frac{- ( - 4 - f ) - ( - f - 4 )}{2 \cdot 1}

x = \frac{- ( - 4 - f ) - f - 4}{2 \cdot 1} : 0

x = \frac{- ( - 4 - f ) - ( - f - 4 )}{2 \cdot 1} : 4 + f

The solutions to the quadratic equation are:

x = 0, x = 4 + f

x - x^{2} = 5

0 = 8 x - 4 x^{2}

2 x^{2} + 3 a^{2} = 7 a x

x^{2} - 4 = 0

10 x + 30 = - x^{2}

What are the solutions to the equation solvefor x,fx=x^2-4x ?
The solutions to the equation solvefor x,fx=x^2-4x are x=0,x=4+f
Find the zeros of solvefor x,fx=x^2-4x
The zeros of solvefor x,fx=x^2-4x are x=0,x=4+f