What are the solutions to the equation x-x^2=5 ?

The solutions to the equation x-x^2=5 are x= 1/2-i(sqrt(19))/2 ,x= 1/2+i(sqrt(19))/2

Find the zeros of x-x^2=5

The zeros of x-x^2=5 are x= 1/2-i(sqrt(19))/2 ,x= 1/2+i(sqrt(19))/2

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x - x^{2} = 5

x = \frac{1}{2} - i \frac{19}{2}, x = \frac{1}{2} + i \frac{19}{2}

Solution steps

x - x^{2} = 5

Move

5

to the left side

x - x^{2} - 5 = 0

Write in the standard form

a x^{2} + b x + c = 0

- x^{2} + x - 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 ( - 1 ) ( - 5 )}{2 ( - 1 )}

Simplify

1^{2} - 4 (- 1) (- 5) : 19 i

x_{1, 2} = \frac{- 1 \pm 19 i}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- 1 + 19 i}{2 ( - 1 )}, x_{2} = \frac{- 1 - 19 i}{2 ( - 1 )}

x = \frac{- 1 + 19 i}{2 ( - 1 )} : \frac{1}{2} - i \frac{19}{2}

x = \frac{- 1 - 19 i}{2 ( - 1 )} : \frac{1}{2} + i \frac{19}{2}

The solutions to the quadratic equation are:

x = \frac{1}{2} - i \frac{19}{2}, x = \frac{1}{2} + i \frac{19}{2}

0 = 8 x - 4 x^{2}

2 x^{2} + 3 a^{2} = 7 a x

x^{2} - 4 = 0

10 x + 30 = - x^{2}

3 y^{2} + 8 y = 2 y + 9

What are the solutions to the equation x-x^2=5 ?
The solutions to the equation x-x^2=5 are x= 1/2-i(sqrt(19))/2 ,x= 1/2+i(sqrt(19))/2
Find the zeros of x-x^2=5
The zeros of x-x^2=5 are x= 1/2-i(sqrt(19))/2 ,x= 1/2+i(sqrt(19))/2