What are the solutions to the equation 15x^2+8x-12=0 ?

The solutions to the equation 15x^2+8x-12=0 are x= 2/3 ,x=-6/5

Find the zeros of 15x^2+8x-12=0

The zeros of 15x^2+8x-12=0 are x= 2/3 ,x=-6/5

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15 x^{2} + 8 x - 12 = 0

x = \frac{2}{3}, x = - \frac{6}{5}

Decimal Notation

x = 0.66666 \dots, x = - 1.2

Solution steps

15 x^{2} + 8 x - 12 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 15 ( - 12 )}{2 \cdot 15}

8^{2} - 4 \cdot 15 (- 12) = 28

x_{1, 2} = \frac{- 8 \pm 28}{2 \cdot 15}

Separate the solutions

x_{1} = \frac{- 8 + 28}{2 \cdot 15}, x_{2} = \frac{- 8 - 28}{2 \cdot 15}

x = \frac{- 8 + 28}{2 \cdot 15} : \frac{2}{3}

x = \frac{- 8 - 28}{2 \cdot 15} : - \frac{6}{5}

The solutions to the quadratic equation are:

x = \frac{2}{3}, x = - \frac{6}{5}

0 = 40 - 5 t - 5 t^{2}

(6 x + 4)^{2} = 16

x, 9 x^{2} + 12 x y + 4 y^{2} - 18 x - 16 y - 11 = 0

16 x^{2} - 235 x + 151 = 0

3 x^{2} + 1 = - 13 x - 3

What are the solutions to the equation 15x^2+8x-12=0 ?
The solutions to the equation 15x^2+8x-12=0 are x= 2/3 ,x=-6/5
Find the zeros of 15x^2+8x-12=0
The zeros of 15x^2+8x-12=0 are x= 2/3 ,x=-6/5