What are the solutions to the equation 5x^2-10x+9=3 ?

The solutions to the equation 5x^2-10x+9=3 are x=1+i(sqrt(5))/5 ,x=1-i(sqrt(5))/5

Find the zeros of 5x^2-10x+9=3

The zeros of 5x^2-10x+9=3 are x=1+i(sqrt(5))/5 ,x=1-i(sqrt(5))/5

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5 x^{2} - 10 x + 9 = 3

x = 1 + i \frac{5}{5}, x = 1 - i \frac{5}{5}

Solution steps

5 x^{2} - 10 x + 9 = 3

Move

3

to the left side

5 x^{2} - 10 x + 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 10 ) \pm ( - 10 ) ^{2} - 4 \cdot 5 \cdot 6}{2 \cdot 5}

Simplify

(- 10)^{2} - 4 \cdot 5 \cdot 6 : 25 i

x_{1, 2} = \frac{- ( - 10 ) \pm 2 5 i}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- ( - 10 ) + 2 5 i}{2 \cdot 5}, x_{2} = \frac{- ( - 10 ) - 2 5 i}{2 \cdot 5}

x = \frac{- ( - 10 ) + 2 5 i}{2 \cdot 5} : 1 + i \frac{5}{5}

x = \frac{- ( - 10 ) - 2 5 i}{2 \cdot 5} : 1 - i \frac{5}{5}

The solutions to the quadratic equation are:

x = 1 + i \frac{5}{5}, x = 1 - i \frac{5}{5}

- 2 x^{2} + 11 x + 7 = 10 + 4 x

x^{2} + 10 x - 11 = 0

x^{2} - (3 \cdot (- 4)) = 100 + 3.5 - (\frac{- 24}{2})

- x^{2} - \frac{11}{3} x + 2 = 0

x, f = 9 x^{2} - 5 x y + 7 y^{2} - 120

What are the solutions to the equation 5x^2-10x+9=3 ?
The solutions to the equation 5x^2-10x+9=3 are x=1+i(sqrt(5))/5 ,x=1-i(sqrt(5))/5
Find the zeros of 5x^2-10x+9=3
The zeros of 5x^2-10x+9=3 are x=1+i(sqrt(5))/5 ,x=1-i(sqrt(5))/5