What are the solutions to the equation -2x^2+11x+7=10+4x ?

The solutions to the equation -2x^2+11x+7=10+4x are x= 1/2 ,x=3

Find the zeros of -2x^2+11x+7=10+4x

The zeros of -2x^2+11x+7=10+4x are x= 1/2 ,x=3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

- 2 x^{2} + 11 x + 7 = 10 + 4 x

x = \frac{1}{2}, x = 3

Decimal Notation

x = 0.5, x = 3

Solution steps

- 2 x^{2} + 11 x + 7 = 10 + 4 x

Move

4 x

to the left side

- 2 x^{2} + 7 x + 7 = 10

Move

10

to the left side

- 2 x^{2} + 7 x - 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 ( - 2 ) ( - 3 )}{2 ( - 2 )}

7^{2} - 4 (- 2) (- 3) = 5

x_{1, 2} = \frac{- 7 \pm 5}{2 ( - 2 )}

Separate the solutions

x_{1} = \frac{- 7 + 5}{2 ( - 2 )}, x_{2} = \frac{- 7 - 5}{2 ( - 2 )}

x = \frac{- 7 + 5}{2 ( - 2 )} : \frac{1}{2}

x = \frac{- 7 - 5}{2 ( - 2 )} : 3

The solutions to the quadratic equation are:

x = \frac{1}{2}, x = 3

x^{2} + 10 x - 11 = 0

x^{2} - (3 \cdot (- 4)) = 100 + 3.5 - (\frac{- 24}{2})

- x^{2} - \frac{11}{3} x + 2 = 0

x, f = 9 x^{2} - 5 x y + 7 y^{2} - 120

k^{2} + 2 k + 3 = 0

What are the solutions to the equation -2x^2+11x+7=10+4x ?
The solutions to the equation -2x^2+11x+7=10+4x are x= 1/2 ,x=3
Find the zeros of -2x^2+11x+7=10+4x
The zeros of -2x^2+11x+7=10+4x are x= 1/2 ,x=3