What are the solutions to the equation (7x^2-x)/2 =168 ?

The solutions to the equation (7x^2-x)/2 =168 are x=7,x=-48/7

Find the zeros of (7x^2-x)/2 =168

The zeros of (7x^2-x)/2 =168 are x=7,x=-48/7

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\frac{7 x ^{2} - x}{2} = 168

x = 7, x = - \frac{48}{7}

Decimal Notation

x = 7, x = - 6.85714 \dots

Solution steps

\frac{7 x ^{2} - x}{2} = 168

Multiply both sides by

2

7 x^{2} - x = 336

Move

336

to the left side

7 x^{2} - x - 336 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 7 ( - 336 )}{2 \cdot 7}

(- 1)^{2} - 4 \cdot 7 (- 336) = 97

x_{1, 2} = \frac{- ( - 1 ) \pm 97}{2 \cdot 7}

Separate the solutions

x_{1} = \frac{- ( - 1 ) + 97}{2 \cdot 7}, x_{2} = \frac{- ( - 1 ) - 97}{2 \cdot 7}

x = \frac{- ( - 1 ) + 97}{2 \cdot 7} : 7

x = \frac{- ( - 1 ) - 97}{2 \cdot 7} : - \frac{48}{7}

The solutions to the quadratic equation are:

x = 7, x = - \frac{48}{7}

v, \frac{1}{2} m v^{2} = g h (m + m)

4 u^{2} = - 12 u - 5

a^{2} + 1 7^{2} = 1 9^{2}

25 = a^{2} + 2 a + 10

x^{2} - 6 x - 2 = 0

What are the solutions to the equation (7x^2-x)/2 =168 ?
The solutions to the equation (7x^2-x)/2 =168 are x=7,x=-48/7
Find the zeros of (7x^2-x)/2 =168
The zeros of (7x^2-x)/2 =168 are x=7,x=-48/7