What are the solutions to the equation 25=a^2+2a+10 ?

The solutions to the equation 25=a^2+2a+10 are a=3,a=-5

Find the zeros of 25=a^2+2a+10

The zeros of 25=a^2+2a+10 are a=3,a=-5

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25 = a^{2} + 2 a + 10

a = 3, a = - 5

Solution steps

25 = a^{2} + 2 a + 10

Switch sides

a^{2} + 2 a + 10 = 25

Move

25

to the left side

a^{2} + 2 a - 15 = 0

Solve with the quadratic formula

a_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 1 \cdot ( - 15 )}{2 \cdot 1}

2^{2} - 4 \cdot 1 \cdot (- 15) = 8

a_{1, 2} = \frac{- 2 \pm 8}{2 \cdot 1}

Separate the solutions

a_{1} = \frac{- 2 + 8}{2 \cdot 1}, a_{2} = \frac{- 2 - 8}{2 \cdot 1}

a = \frac{- 2 + 8}{2 \cdot 1} : 3

a = \frac{- 2 - 8}{2 \cdot 1} : - 5

The solutions to the quadratic equation are:

a = 3, a = - 5

x^{2} - 6 x - 2 = 0

7 x^{2} - 2 x - 4 = 0

p (5 p - 3) = 0

3 x^{2} = 75

(250 + 10 x) (70 - 2 x) = 17980

What are the solutions to the equation 25=a^2+2a+10 ?
The solutions to the equation 25=a^2+2a+10 are a=3,a=-5
Find the zeros of 25=a^2+2a+10
The zeros of 25=a^2+2a+10 are a=3,a=-5