What is the answer to (x+2)^2-(x-3)=x^2+6x-3 ?

The answer to (x+2)^2-(x-3)=x^2+6x-3 is x= 10/3

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(x+2)^2-(x-3)=x^2+6x-3

(x + 2)^{2} - (x - 3) = x^{2} + 6 x - 3

x = \frac{10}{3}

Decimal Notation

x = 3.33333 \dots

Solution steps

(x + 2)^{2} - (x - 3) = x^{2} + 6 x - 3

Expand

(x + 2)^{2} - (x - 3) : x^{2} + 3 x + 7

x^{2} + 3 x + 7 = x^{2} + 6 x - 3

Move

7

to the right side

x^{2} + 3 x = x^{2} + 6 x - 10

Subtract

x^{2} + 6 x

from both sides

x^{2} + 3 x - (x^{2} + 6 x) = x^{2} + 6 x - 10 - (x^{2} + 6 x)

Simplify

- 3 x = - 10

Divide both sides by

- 3

x = \frac{10}{3}

\frac{2 x + 1}{5} - \frac{x + 1}{3} = 2 [\frac{3 x}{10} - (\frac{x}{6} - 1)]

y, (D^{2} - 4) (D + 2) y = 0

t, \frac{d S}{d t} = a \cdot v

x + 4 = 3 (x - 4)

x, ln (y) = x - 2

What is the answer to (x+2)^2-(x-3)=x^2+6x-3 ?
The answer to (x+2)^2-(x-3)=x^2+6x-3 is x= 10/3
Solve for x: (x+2)^2-(x-3)=x^2+6x-3
The solution is x= 10/3