What is the answer to 2x+a-4=(b-3)x+ab ?

The answer to 2x+a-4=(b-3)x+ab is x=(ab-a+4)/(-b+5);\quad b\ne 5

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2x+a-4=(b-3)x+ab

2 x + a - 4 = (b - 3) x + ab

x = \frac{ab - a + 4}{- b + 5}; b \neq = 5

Solution steps

2 x + a - 4 = (b - 3) x + ab

Expand

(b - 3) x + ab : b x - 3 x + ab

2 x + a - 4 = b x - 3 x + ab

Move

a

to the right side

2 x - 4 = b x - 3 x + ab - a

Move

4

to the right side

2 x = b x - 3 x + ab - a + 4

Subtract

b x - 3 x

from both sides

2 x - (b x - 3 x) = b x - 3 x + ab - a + 4 - (b x - 3 x)

Simplify

- b x + 5 x = ab - a + 4

Factor

- b x + 5 x : x (- b + 5)

x (- b + 5) = ab - a + 4

Divide both sides by

- b + 5; b \neq = 5

x = \frac{ab - a + 4}{- b + 5}; b \neq = 5

\frac{17}{4} - x \cdot 1 = \frac{2}{3}

a, (a + \frac{b}{c}) (d - e) = f

x, \frac{x + 1}{3} - \frac{y - 1}{6} = - 1

\frac{y - 6}{4} = \frac{y}{7}

(x - 5) 2 - 9 = 0

What is the answer to 2x+a-4=(b-3)x+ab ?
The answer to 2x+a-4=(b-3)x+ab is x=(ab-a+4)/(-b+5);\quad b\ne 5