What is the answer to log_{10}(3)(x+2)=-1 ?

The answer to log_{10}(3)(x+2)=-1 is x=-1/(log_{10)(3)}-2

Solve for x: log_{10}(3)(x+2)=-1

The solution is x=-1/(log_{10)(3)}-2

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lo g_{10} (3) (x + 2) = - 1

x = - \frac{1}{lo g _{10} ( 3 )} - 2

Decimal Notation

x = - 4.09590 \dots

Solution steps

lo g_{10} (3) (x + 2) = - 1

Divide both sides by

lo g_{10} (3)

x + 2 = - \frac{1}{lo g _{10} ( 3 )}

Move

2

to the right side

x = - \frac{1}{lo g _{10} ( 3 )} - 2

\frac{9 ( t - 9 )}{10} + 1 = t - \frac{3 t - 5}{2} + \frac{23}{5}

3 x - 10 = 2 x + 45

(x + \frac{1}{9}) (x + \frac{5}{3}) = (x + \frac{5}{3}) (x + 10)

y, y = \frac{6}{5} (1 - e^{- 20 t})

lo g_{2} (4 (90) + 6) + lo g_{2} (90) = 2

What is the answer to log_{10}(3)(x+2)=-1 ?
The answer to log_{10}(3)(x+2)=-1 is x=-1/(log_{10)(3)}-2
Solve for x: log_{10}(3)(x+2)=-1
The solution is x=-1/(log_{10)(3)}-2