What is the answer to (2t+13)/3-(6-t)/4 =1 ?

The answer to (2t+13)/3-(6-t)/4 =1 is t=-2

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(2t+13)/3-(6-t)/4 =1

\frac{2 t + 13}{3} - \frac{6 - t}{4} = 1

t = - 2

Solution steps

\frac{2 t + 13}{3} - \frac{6 - t}{4} = 1

Multiply by LCM

4 (2 t + 13) - 3 (- t + 6) = 12

Expand

4 (2 t + 13) - 3 (- t + 6) : 11 t + 34

11 t + 34 = 12

Move

34

to the right side

11 t = - 22

Divide both sides by

11

t = - 2

x, d \cdot (- 3 + x) = k x + 9

\frac{1}{9} [3 x - 6 - 5 (\frac{7 x}{2} - 5)] + 13 (x - 5) + \frac{1}{4} = 0

\frac{5 - x}{2} + 4 (x - 1) = 2 x - \frac{3 x + 1}{2}

c, z = 27 c i s (24 0^{\circ})

4 (\frac{x}{2} - \frac{1}{2}) = 9 (\frac{x}{3} + \frac{1}{3}) - 5 (\frac{x}{5} + \frac{4}{5})

What is the answer to (2t+13)/3-(6-t)/4 =1 ?
The answer to (2t+13)/3-(6-t)/4 =1 is t=-2
Solve for t: (2t+13)/3-(6-t)/4 =1
The solution is t=-2