What is the answer to solvefor c,z=27cis(240) ?

The answer to solvefor c,z=27cis(240) is c=-(iz)/(27*240s);\quad s\ne 0

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solvefor c,z=27cis(240)

solve for

c, z = 27 c i s (24 0^{\circ})

c = - \frac{i z}{27 \cdot 24 0 ^{\circ} s}; s \neq = 0

Solution steps

z = 27 c i s (24 0^{\circ})

Switch sides

27 c i s 24 0^{\circ} = z

Divide both sides by

27 i s \cdot 24 0^{\circ}; s \neq = 0

c = - \frac{i z}{27 \cdot 24 0 ^{\circ} s}; s \neq = 0

4 (\frac{x}{2} - \frac{1}{2}) = 9 (\frac{x}{3} + \frac{1}{3}) - 5 (\frac{x}{5} + \frac{4}{5})

x, P = y - x (y^{2} + 2)

\frac{2 v - 3}{4} = \frac{6 v + 7}{3}

C - (- \frac{2}{3}) + 1 = \frac{1585}{927}

12 - 2 (x + 1) = 5

What is the answer to solvefor c,z=27cis(240) ?
The answer to solvefor c,z=27cis(240) is c=-(iz)/(27*240s);\quad s\ne 0