What are the solutions to the equation 6x^2-8x-1=0 ?

The solutions to the equation 6x^2-8x-1=0 are x=(4+sqrt(22))/6 ,x=(4-sqrt(22))/6

Find the zeros of 6x^2-8x-1=0

The zeros of 6x^2-8x-1=0 are x=(4+sqrt(22))/6 ,x=(4-sqrt(22))/6

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6 x^{2} - 8 x - 1 = 0

x = \frac{4 + 22}{6}, x = \frac{4 - 22}{6}

Decimal Notation

x = 1.44840 \dots, x = - 0.11506 \dots

Solution steps

6 x^{2} - 8 x - 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 6 ( - 1 )}{2 \cdot 6}

(- 8)^{2} - 4 \cdot 6 (- 1) = 222

x_{1, 2} = \frac{- ( - 8 ) \pm 2 22}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- ( - 8 ) + 2 22}{2 \cdot 6}, x_{2} = \frac{- ( - 8 ) - 2 22}{2 \cdot 6}

x = \frac{- ( - 8 ) + 2 22}{2 \cdot 6} : \frac{4 + 22}{6}

x = \frac{- ( - 8 ) - 2 22}{2 \cdot 6} : \frac{4 - 22}{6}

The solutions to the quadratic equation are:

x = \frac{4 + 22}{6}, x = \frac{4 - 22}{6}

2 x (x - 2) = 5

5 x^{2} - 38 x - 16

200 \cdot \frac{5280}{3600}

(x + 3)^{2} - 5 = 4

20 x^{2} + 12 x + 1 = 0

What are the solutions to the equation 6x^2-8x-1=0 ?
The solutions to the equation 6x^2-8x-1=0 are x=(4+sqrt(22))/6 ,x=(4-sqrt(22))/6
Find the zeros of 6x^2-8x-1=0
The zeros of 6x^2-8x-1=0 are x=(4+sqrt(22))/6 ,x=(4-sqrt(22))/6