What are the solutions to the equation x^2+10x+4=0 ?

The solutions to the equation x^2+10x+4=0 are x=-5+sqrt(21),x=-5-sqrt(21)

Find the zeros of x^2+10x+4=0

The zeros of x^2+10x+4=0 are x=-5+sqrt(21),x=-5-sqrt(21)

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x^{2} + 10 x + 4 = 0

x = - 5 + 21, x = - 5 - 21

Decimal Notation

x = - 0.41742 \dots, x = - 9.58257 \dots

Solution steps

x^{2} + 10 x + 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 \cdot 1 \cdot 4}{2 \cdot 1}

1 0^{2} - 4 \cdot 1 \cdot 4 = 221

x_{1, 2} = \frac{- 10 \pm 2 21}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 10 + 2 21}{2 \cdot 1}, x_{2} = \frac{- 10 - 2 21}{2 \cdot 1}

x = \frac{- 10 + 2 21}{2 \cdot 1} : - 5 + 21

x = \frac{- 10 - 2 21}{2 \cdot 1} : - 5 - 21

The solutions to the quadratic equation are:

x = - 5 + 21, x = - 5 - 21

(\frac{4}{6})^{6}

(x + y + z)^{3} - x^{3} - y^{3} - z^{3}

34.46 + \frac{50}{40}

9 x^{2} - 42 x + 49 = 0

3 x + 2 = x - 7

What are the solutions to the equation x^2+10x+4=0 ?
The solutions to the equation x^2+10x+4=0 are x=-5+sqrt(21),x=-5-sqrt(21)
Find the zeros of x^2+10x+4=0
The zeros of x^2+10x+4=0 are x=-5+sqrt(21),x=-5-sqrt(21)