What is the answer to x^2+2x+1=(x+1)(x+1) ?

The answer to x^2+2x+1=(x+1)(x+1) is True for all x

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x^2+2x+1=(x+1)(x+1)

x^{2} + 2 x + 1 = (x + 1) (x + 1)

True for all x

Solution steps

x^{2} + 2 x + 1 = (x + 1) (x + 1)

Expand

(x + 1) (x + 1) : x^{2} + 2 x + 1

x^{2} + 2 x + 1 = x^{2} + 2 x + 1

Move

1

to the right side

x^{2} + 2 x = x^{2} + 2 x

Subtract

x^{2} + 2 x

from both sides

x^{2} + 2 x - (x^{2} + 2 x) = x^{2} + 2 x - (x^{2} + 2 x)

Simplify

0 = 0

Both sides are equal

True for all x

3 x + 1 = - 2 x + 36

2 (x - 2 x) = 3 (5 x - 3 x)

x, y = f^{- 1} (x)

44 + 56 + 17 x - 5 = 180

x - \frac{1}{a} = \frac{x}{a}

What is the answer to x^2+2x+1=(x+1)(x+1) ?
The answer to x^2+2x+1=(x+1)(x+1) is True for all x
Solve for x: x^2+2x+1=(x+1)(x+1)
The solution is True for all x