What is (4*16*27*3^{-2})/(2^6*3^{-2)*3^3*2^6} ?

The solution to (4*16*27*3^{-2})/(2^6*3^{-2)*3^3*2^6} is 1/64

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simplify (416273^{-2})/(2^63^{-2)3^32^6}

simplify

\frac{4 \cdot 16 \cdot 27 \cdot 3 ^{- 2}}{2 ^{6} \cdot 3 ^{- 2} \cdot 3 ^{3} \cdot 2 ^{6}}

\frac{1}{64}

Decimal Notation

0.015625

Solution steps

\frac{4 \cdot 16 \cdot 27 \cdot 3 ^{- 2}}{2 ^{6} \cdot 3 ^{- 2} \cdot 3 ^{3} \cdot 2 ^{6}}

Cancel the common factor:

3^{- 2}

= \frac{4 \cdot 16 \cdot 27}{2 ^{6} \cdot 3 ^{3} \cdot 2 ^{6}}

Factor the number:

4 = 2^{2}

= \frac{2 ^{2} \cdot 16 \cdot 27}{2 ^{6} \cdot 3 ^{3} \cdot 2 ^{6}}

\frac{2 ^{2}}{2 ^{6}} = \frac{1}{2 ^{4}}

= \frac{16 \cdot 27}{2 ^{4} \cdot 3 ^{3} \cdot 2 ^{6}}

Factor the number:

16 = 2^{4}

= \frac{2 ^{4} \cdot 27}{2 ^{4} \cdot 3 ^{3} \cdot 2 ^{6}}

Cancel the common factor:

2^{4}

= \frac{27}{3 ^{3} \cdot 2 ^{6}}

Factor the number:

27 = 3^{3}

= \frac{3 ^{3}}{3 ^{3} \cdot 2 ^{6}}

Cancel the common factor:

3^{3}

= \frac{1}{2 ^{6}}

2^{6} = 64

= \frac{1}{64}

7 b - 4 \leq 10

x < 8

3 x^{3} - 5 x^{2} + x + 1

\frac{2}{13}

x (3 x - 8) = 11

What is (4*16*27*3^{-2})/(2^6*3^{-2)*3^3*2^6} ?
The solution to (4*16*27*3^{-2})/(2^6*3^{-2)*3^3*2^6} is 1/64