What is the answer to A=(x+5)^2-(x+4)^2-(x-3)^2+(x-4)^2 ?

The answer to A=(x+5)^2-(x+4)^2-(x-3)^2+(x-4)^2 is True for all x;\quad 16=A

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A=(x+5)^2-(x+4)^2-(x-3)^2+(x-4)^2

A = (x + 5)^{2} - (x + 4)^{2} - (x - 3)^{2} + (x - 4)^{2}

True for all x; 16 = A

Solution steps

A = (x + 5)^{2} - (x + 4)^{2} - (x - 3)^{2} + (x - 4)^{2}

Switch sides

(x + 5)^{2} - (x + 4)^{2} - (x - 3)^{2} + (x - 4)^{2} = A

Expand

(x + 5)^{2} - (x + 4)^{2} - (x - 3)^{2} + (x - 4)^{2} : 16

16 = A

Both sides are equal

True for all x; 16 = A

2 x - (lo g_{3} (4) + x + 1) + 3 = 0

5 x + 4 = 2 x + 1

2 x + 7 = 17

x + 4 = - 9 - 3 (x - 5) + 8 x

a, \frac{a}{b + c} = \frac{a}{b} + \frac{a}{c}

What is the answer to A=(x+5)^2-(x+4)^2-(x-3)^2+(x-4)^2 ?
The answer to A=(x+5)^2-(x+4)^2-(x-3)^2+(x-4)^2 is True for all x;\quad 16=A