What is the answer to solvefor a, a/(b+c)= a/b+a/c ?

The answer to solvefor a, a/(b+c)= a/b+a/c is a=0;\quad bc(b+c)\ne 0

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

solvefor a, a/(b+c)= a/b+a/c

solve for

a, \frac{a}{b + c} = \frac{a}{b} + \frac{a}{c}

a = 0; b c (b + c) \neq = 0

Solution steps

\frac{a}{b + c} = \frac{a}{b} + \frac{a}{c}

Multiply by LCM

ab c = a c (b + c) + ab (b + c); b c (b + c) \neq = 0

Expand

a c (b + c) + ab (b + c) : a b^{2} + a c^{2} + 2 ab c

ab c = a b^{2} + a c^{2} + 2 ab c; b c (b + c) \neq = 0

Subtract

a b^{2} + a c^{2} + 2 ab c

from both sides

ab c - (a b^{2} + a c^{2} + 2 ab c) = a b^{2} + a c^{2} + 2 ab c - (a b^{2} + a c^{2} + 2 ab c); b c (b + c) \neq = 0

Simplify

- a b^{2} - a c^{2} - ab c = 0; b c (b + c) \neq = 0

Factor

- a b^{2} - a c^{2} - ab c : - a (b^{2} + c^{2} + b c)

- a (b^{2} + c^{2} + b c) = 0; b c (b + c) \neq = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

a = 0; b c (b + c) \neq = 0

y = - 2 (1) + 3

4 z = 10

b, c^{2} - \frac{5}{2} b = 2

lo g_{10} (2) (9 x) - 4 lo g_{10} (2) (4) = 1

x, 3 (x - 1) + 2 y + 1 = 0

What is the answer to solvefor a, a/(b+c)= a/b+a/c ?
The answer to solvefor a, a/(b+c)= a/b+a/c is a=0;\quad bc(b+c)\ne 0